[LeetCode 136] Single Number

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Diffculty
Easy

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Analysis

class Solution { public: int singleNumber(vector& A) { int res = 0; for(int i = 0; i < (int)A.size(); ++i){ res ^= A[i]; } return res; } };

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